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Questions  

The maximum acceleration of a particle executing simple harmonic motion is ‘α’ and the maximum velocity is ‘β.  The frequency of the SHM is given by the expression

a
2παβ
b
αβ2π
c
2πβα
d
α2πβ

detailed solution

Correct option is D

maximum acceleration α=ω2A----1 maximum velocity   β= Aω------ 2 dividing 1 by 2  ω=αβ frequency n=ω2π=α2πβ

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