The maximum acceleration of a particle executing simple harmonic motion is ‘α’ and the maximum velocity is ‘β. The frequency of the SHM is given by the expression
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a
2παβ
b
αβ2π
c
2πβα
d
α2πβ
answer is D.
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Detailed Solution
maximum acceleration α=ω2A----1 maximum velocity β= Aω------ 2 dividing 1 by 2 ω=αβ frequency n=ω2π=α2πβ