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Questions  

The maximum acceleration of a particle in SHM is made twice keeping the maximum speed to be constant. It is possible when

a
amplitude of oscillation is doubled while frequency remains constant
b
amplitude of oscillation is doubled while frequency is halved
c
amplitude of oscillation is halved while frequency is doubled
d
amplitude of oscillation remains constant while frequency is doubled

detailed solution

Correct option is C

amax=Aω2   ........(1)vmax=Aω      .......(2)⇒amax=vmaxωSince,  vmax is constant, to double amax , ω should be doubled.From (1), A should be halved.

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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