Questions
The maximum angular speed of the electron of a hydrogen atom in a stationary orbit is
a
6.2×1015rads−1
b
4.1×1016rads−1
c
24×1010rads−1
d
9.2×106rads−1
detailed solution
Correct option is B
Maximum angular speed will be in its ground state. Hence,ωmax=v1r1=2.2×1060.529×10−10=4.1×1016rads−1Talk to our academic expert!
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Which of the following is quantised according to Bohr’s theory of hydrogen atom
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