The maximum displacement of an oscillating particle is 0.05m. If its time period is 1.57s(i) What is the velocity at the mean position ? (ii) What is its acceleration at the extreme position ?

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0.2 ms–1, 0.2ms–2

0.8 ms–1, 0.8ms–2

0.2 ms–1, 0.8ms–2

0.8 ms–1, 0.2ms–2

answer is C.

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Detailed Solution

Max. displacements = AmplitudeA = 0.05m ; T = 1.57secvelocity at mean position Acceleration at extreme position[-ve sign only direction]

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