The maximum distance between the transmitting and receiving TV towers is $$64$$ Km. If the ratio of the heights of the TV transmitting tower to receiving tower is $$4$$:$$9$$, the heights of the transmitting and receiving towers are

Question

Infinity Learn · Accepted Answer

Given : d $$=$$ $$64$$ Km , $$hThR=49$$  We know, $$d=2RhT+2RhR$$ ⇒$$64000=2R49hR+2RhR$$ ⇒$$64000=2RhR23+2RhR$$ ⇒$$64000=2RhR23+1$$ ⇒$$64000$$×$$35=2RhR$$ ⇒$$64000$$×$$35$$×$$64000$$×$$35=2RhR$$ ⇒$$64000$$×$$64000$$×$$925=2$$×$$6400$$×$$1000$$×hR ⇒$$320$$×$$925=hR$$ ⇒hR $$=$$ $$115.2$$ m  ∴ $$hT=49hR$$ $$=$$ $$49$$× $$115.2$$  $$=$$ $$51.2$$ m

The maximum distance between the transmitting and receiving TV towers is 64 Km. If the ratio of the heights of the TV transmitting tower to receiving tower is 4:9, the heights of the transmitting and receiving towers are

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