The maximum energy Kmax of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how Kmaxvaries with v. The slope of the graph is equal to
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a
the charge of an electron
b
the charge of mass ratio of an electron
c
the work function of the emitter in the cell
d
Planck’s constant.
answer is D.
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Detailed Solution
Since Kmax=hv−v0, the slope of the graph of Kmax against v is h, the Planck's constant.
The maximum energy Kmax of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how Kmaxvaries with v. The slope of the graph is equal to