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The maximum energy $K_{max}$ of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how $K_{max}$ varies with v. The slope of the graph is equal to

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the charge of an electron

the charge of mass ratio of an electron

the work function of the emitter in the cell

Planck’s constant.

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detailed solution

Correct option is D

Since Kmax=hv−v0, the slope of the graph of Kmax against v is h, the Planck's constant.

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The maximum energy Kmax of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how Kmaxvaries with v. The slope of the graph is equal to

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The maximum energy $K_{max}$ of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how $K_{max}$ varies with v. The slope of the graph is equal to