The maximum height attained by a projectile is increased by 10% by increasing its speed of projection, without changing the angle of projection. The percentage increase in the horizontal range will be

we know that h=u2sin2⁡θ2gLet δh be increase in h when u changes by δu. Henceδh=2uδusin2⁡θ2gor         δhh=2δuuaGiven that h is increased by 10%, i.e., δh/h=0⋅1 So,         0⋅1=2δuu                   …. (1)Further,    R=u2sin⁡2θgor                 δR=2uδusin⁡2θg    So,             δRR=2δuu              …… (2)From eqs. (1) and (2), we getδRR=0⋅1  or  δR=0⋅1×RHence R is also increased by 10%.