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The maximum height attained by a projectile is increased by 10%. Keeping the angle of projection constant, what is the percentage increase in the time of flight? 

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a
5 %
b
10 %
c
20 %
d
40 %

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detailed solution

Correct option is A

hT2= u2sin2θ2g×g24u2sin2θ = g8Thus ∆hh = 2∆TT i.e., ∆TT = 12∆hh or 100 × ∆Th = 12[∆hh×100] = 102 = 5%


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