Q.
The maximum height reached by projectile is 4 m. The horizontal range is 12 m. The velocity of projection in ms-1 is (g is acceleration due to gravity)
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a
5g/2
b
3g/2
c
13g/2
d
15g/2
answer is A.
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Detailed Solution
tanθ=4HR=4×412=43 ⇒ sinθ=45 H=u2sin2θ2g⇒ u=2gHsinθ=2×g×44/5=5g2
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