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Q.

The maximum height reached by projectile is 4 m. The horizontal range is 12 m. The velocity of projection in ms-1 is (g is acceleration due to gravity)

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a

5g/2

b

3g/2

c

13g/2

d

15g/2

answer is A.

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Detailed Solution

tan⁡θ=4HR=4×412=43 ⇒ sin⁡θ=45 H=u2sin2⁡θ2g⇒ u=2gHsin⁡θ=2×g×44/5=5g2

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