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The maximum height reached by a projectile is 4 meters. The horizontal range is 12 meters. Velocity of projection, in ms-1, is (g is acceleration due to gravity)

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a

g25

b

g23

c

1382

d

15g2

answer is A.

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Detailed Solution

4H=R tan ⁡θ⇒4×4=12×tan ⁡θ⇒tan ⁡θ=43Given Hmax=u2sin2⁡θ2g=4⇒u2×45×45×12×10=5u2=125⇒u=55m=5g2

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The maximum height reached by a projectile is 4 meters. The horizontal range is 12 meters. Velocity of projection, in ms-1, is (g is acceleration due to gravity)