Questions
The maximum height reached by a projectile is 4 meters. The horizontal range is 12 meters. Velocity of projection, in ms-1, is (g is acceleration due to gravity)
detailed solution
Correct option is A
4H=R tan θ⇒4×4=12×tan θ⇒tan θ=43Given Hmax=u2sin2θ2g=4⇒u2×45×45×12×10=5u2=125⇒u=55m=5g2Talk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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