Q.
The maximum height reached by a projectile is 4 meters. The horizontal range is 12 meters. Velocity of projection , in ms-1 , is (g is acceleration due to gravity)
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a
5g2
b
3g2
c
13g2
d
15g2
answer is A.
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Detailed Solution
R=12m HR=14tanθH=4m 412=14tanθtanθ=43 sinθ=45H=u2sin2θ2g H=u21625×2gu2=100×2g16u=5g/2
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