Questions
The maximum horizontal range of projectile is
detailed solution
Correct option is A
Horizontal range is maximum, whenθ=450 Horizontal range, R=u2 sin 2θ/g ∴ 400=u2sin2×450g or u2g=400 …(i)Maximum height,H=u2sin24502g=4002×12=100 m .Talk to our academic expert!
Similar Questions
The equation of trajectory of projectile is given by where x and y are in metre. The maximum range of the projectile is
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