The maximum intensity in Young's double slit experiment is I0. Distance between the slits is d = 5, where is the wavelength of monochromatic light used in the experiment. The intensity of light in front of one of the slits on a screen at a distance D = 10d is
Suppose P is a point in front of one slit at which intensity is I0. From figure, it is clear that . Path difference between the waves reaching at P is
Hence corresponding phase difference is given by
Resultant intensity at P is