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Q.

Maximum kinetic energy of the positive ion in the cyclotron is (r0 =Radius of cyclotron ,q =charge of ion ,m = mass of ion )

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a

q2Br02m

b

qB2r02m

c

q2B2r022m

d

qBr0 2m2

answer is C.

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Detailed Solution

Kmax  = 12  mv2   and  r0 = mvqB  ⇒  v=qBr0mKmax  = 12  m qBr0m2 = q2B2r022m
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