Modulation

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The maximum and minimum amplitude of an amplitude modulated wave is 16 V and 8 V respectively. The modulation index for this amplitude modulated wave is $x \times 10^{- 2}$ . The value of $x$ is _______.

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Solution

$\begin{array}{l} Given : \frac{E_{max}}{E_{min}} = \frac{16}{8} \\ \Rightarrow \frac{E_{c} (1 + m)}{E_{c} (1 - m)} = \frac{16}{8} \\ \Rightarrow 1 + m = 2 - 2 m \\ \Rightarrow 3 m = 1 \\ \Rightarrow m = \frac{1}{3} \\ \Rightarrow m = \frac{1}{3} = 0.3333 = x \times 10^{- 2} \\ \Rightarrow x = 33.33 \end{array}$

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Modulation

Remember concepts with our Masterclasses.

The maximum and minimum amplitude of an amplitude modulated wave is 16 V and 8 V respectively. The modulation index for this amplitude modulated wave is x×10−2. The value of x is _______.

Given : EmaxEmin=168⇒Ec(1+m)Ec(1−m)=168⇒1+m=2−2m⇒3m=1⇒m=13⇒m=13=0.3333=x×10−2⇒x=33.33

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The maximum and minimum amplitude of an amplitude modulated wave is 16 V and 8 V respectively. The modulation index for this amplitude modulated wave is $x \times 10^{- 2}$ . The value of $x$ is _______.