First slide

Gravitational force and laws

Question

The maximum and minimum distances of a comet from the sun are $8 \times 10^{12}$ m and $1.6 \times 10^{12}$ m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?

Moderate

A

12
B

60
C

112
D

6

Solution

By conservation of angular momentum mvr = constant
$\begin{array}{l} v_{min} \times r_{max} = v_{max} \times r_{min} \\ ∴ v_{min} = \frac{60 \times 1 .6 \times 10^{12}}{8 \times 10^{12}} = \frac{60}{5} = 12 m / s \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App