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The maximum peak to peak voltage of an AM wave is 16 mV and the min peak-to-peak voltage in 4mV. The modulation factor is equal to

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a
0.6
b
0.3
c
0.8
d
0.25

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detailed solution

Correct option is A

modulation factor =μ=Emax−Emin2Emax+Emin2=16 x 10−3 − 4 x 10−3216x10−3+4x10−32=1220=35=0.6

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