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Q.

The maximum range of a projectile is 500 m. If the particle is thrown up along a plane, which is inclined at an angle of 30o with the same speed, the distance covered by it along the inclined plane will be

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a

250 m

b

500 m

c

750 m

d

1000 m

answer is B.

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Detailed Solution

For the maximum range θ=45∘.R=u2sin⁡2θg=u2gsin⁡90∘=u2g  or  500=u2gThe distance covered along the inclined plane can be obtained using the equation,    v2−u2=2asor  0−u2=2−gsin⁡30∘s  or  s=u2g=500m
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The maximum range of a projectile is 500 m. If the particle is thrown up along a plane, which is inclined at an angle of 30o with the same speed, the distance covered by it along the inclined plane will be