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Q.

The maximum range of a projectile is 500m. If the particle is thrown up along a frictionless plane, which is inclined at an angle of 300with the same speed, the distance covered by it along the inclined plane will be

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a

250m

b

500m

c

750m

d

1000m

answer is B.

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Detailed Solution

For the maximum range θ=450R=u2sin2θg=u2gsin900=u2gor 500=u2gThe distance covered along the inclined plane cam be obtained using the equation v2−u2=2asOr 0−u2=2(−gsin300)sor s=u2g=500m

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