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The maximum range of a projectile is 500 m. If the particle is thrown up a plane is inclined at an angle of 300 with the same speed, the distance covered by it along the inclined plane will be:

a
250 m
b
500 m
c
750 m
d
100 m

detailed solution

Correct option is B

For the maximum range, θ = 450R = u2sin 2θg = u2gsin 900 = u2gor 500 = u2gThe distance covered along the inclined plane can be obtained using the equationv2-u2 = 2asor 0-u2 = 2(-gsin 300)sor s = u2g = 500 m

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