The maximum speed and acceleration of a particle executing simple harmonic motion are 10cms−1 and 50cms−2 . Magnitude of displacement of the particle when the speed is 2.5cms−1 is

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0.6 cm

1.2 cm

0.8 cm

154 cm

answer is D.

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Detailed Solution

Aω=10----(1) ; Aω2=50 ⇒A=Vmax2amax⇒A=2 cm;⇒ ω=5 rads−1 from (1) using v=ωA2−x2 ⇒2.5=522−x2 ⇒x=±154 cm

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