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Q.

The maximum speed and acceleration of a particle executing simple harmonic  motion are 10cms−1   and 50cms−2  . Magnitude of displacement of the particle when  the speed is 2.5cms−1   is

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a

0.6 cm

b

1.2 cm

c

0.8 cm

d

154 cm

answer is D.

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Detailed Solution

Aω=10----(1) ;   Aω2=50 ⇒A=Vmax2amax⇒A=2  cm;⇒  ω=5  rads−1 from (1) using v=ωA2−x2 ⇒2.5=522−x2 ⇒x=±154 cm
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