First slide

Simple harmonic motion

Question

The maximum speed of a particle executing S.H.M. is $1 m / s$ and its maximum acceleration is $1 .57 m / \sec^{2}$ . The time period of the particle will be

Moderate

A

$\frac{1}{1 .57} \sec$
B

1.57 sec
C

2 sec
D

4 sec

Solution

Given max velocity $ωa = 1$ and maximum acceleration
$ω^{2} a = 1 .57$
$∴ \frac{ω^{2} a}{ωa} = 1 .57 \Rightarrow ω = 1 .57$ $\Rightarrow \frac{2 π}{T} = 1 .57 \Rightarrow T = 4$

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