First slide

Simple hormonic motion

Question

The maximum velocity of a particle executing simple harmonic motion with an amplitude 7mm, is 4.4 m/s. The period of oscillation is :

Easy

A

0.1 sec
B

100 sec
C

0.01 sec
D

10 sec

Solution

$v_{\max} = aω = a (\frac{2 π}{T}) \Rightarrow T = \frac{2 πa}{v_{\max}} = \frac{2 \times 3.14 \times 7 \times 10^{- 3}}{4.4} = 0.01 s$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App