First slide

Law of equipartition of energy

Question

Mean kinetic energy (or average energy) per gm mole of a monoatomic gas is given by

Easy

A

$\frac{3}{2}RT$
B

$\frac{1}{2}KT$
C

$\frac{1}{2}RT$
D

$\frac{3}{2}KT$

Solution

Mean kinetic energy of one mole of an ideal gas = $\frac{f R T}{2}$
For monoatomic gas f = 3. f is degrees of freedom.

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