First slide

Law of equipartition of energy

Question

Mean kinetic energy per gram molecule for diatomic gas is

Moderate

A

$\frac{3}{2} RT$
B

$\frac{4}{2} RT$
C

$\frac{5}{2} RT$
D

$\frac{6}{2} RT$

Solution

Mean kinetic energy U per mole of a gas whose molecules have f degrees of freedom is given by :
$U = \frac{f}{2} RT$
For a diatomic gas molecule.
$f = 5, so U = \frac{5}{2} RT$

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