Measure of two quantities along with the precision of respective measuring instrument is  A = 2.5ms-1 ±0.5ms-1, B = 0.10 s± 0.01 s. The value of AB will be

Given, A= 2.5 ms-1 ± 0.5 ms-1, B = 0.10 s ± 0.0ls           x = AB = (2.5)(0.10) = 0. 25 m          Δxx=ΔAA+ΔBB=0.52.5+0.010.10=0.05+0.0250.25=0.0750.25         ∆x = 0.075 = 0.08 m (rounding off to one significant figure)        AB = (0.25 ± 0.08) m