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Measure of two quantities along with the precision of respective measuring instruments is $A = 2.5 m s^{- 1} = 0.5 m s^{- 1}, B = 0.10 s \pm 0.01 s .$ The value of AB will be

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(0.25±0.08) m

(0.25±0.5) m

(0.25±0.05) m

(0.25±0.135) m

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detailed solution

Correct option is A

A = 2.5 ms-1±0.5 ms-1, B = 0.10s±0.01sx = AB = (2.5)(0.10) = 0.25 m△xx= △AA+△BB = 0.52.5+0.010.10= 0.05+0.0250.25 = 0.0750.25△x = 0.075 = 0.08 m Rounding off to two significant figuresAB = (0.25 ± 0.08) m

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Measure of two quantities along with the precision of respective measuring instruments is A = 2.5 ms-1= 0.5 ms-1, B = 0.10s ±0.01s. The value of AB will be

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Measure of two quantities along with the precision of respective measuring instruments is $A = 2.5 m s^{- 1} = 0.5 m s^{- 1}, B = 0.10 s \pm 0.01 s .$ The value of AB will be