In measuring 'g' using a simple pendulum a student makes a positive error of 1% in length of pendulum and a negative error of 3% in the value of time period. Percentage error in measurement of value of g is

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answer is 3.

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Detailed Solution

T=2πl g⇒T2=4π2l g g∝l T2⇒Δgg=Δll%-2ΔTT% =1%-2 - 3%=7%

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