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Q.

A mercury drop of 1 cm radius is broken into  106 small drops. The energy used will be (surface tension of mercury is 35×10−3N/cm)

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a

4.4×10−3J

b

2.2×10−4J

c

8.8×10−4J

d

104J

answer is A.

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Detailed Solution

E=4πR2Tn1/3−1=4×3.14×10−4×35×10−3106/3−1=4.4×10−3J
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A mercury drop of 1 cm radius is broken into  106 small drops. The energy used will be (surface tension of mercury is 35×10−3N/cm)