First slide

Surface tension and surface energy

Question

A mercury drop of radius 1cm is sprayed into 10⁶ drops of equal size. The energy expended in joules is (surface tension of Mercury is $460 \times 10^{- 3} N / m)$

Moderate

A

0.057
B

5.7
C

$5.7 \times 10^{- 4}$
D

$5.7 \times 10^{- 6}$

Solution

$\begin{matrix} W = TΔA = 4 {πR}^{2} T (n^{1 / 3} - 1) \\ = 4 \times 3 .14 \times {(10^{- 2})}^{2} \times 460 \times 10^{- 3} \times [{(10^{6})}^{1 / 3} - 1] = 0 .057 \end{matrix}$

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