First slide

Law of conservation of angular momentum

Question

A Merry-go-round, made of a ring-like platform of radius R and mass M, is revolving with angular speed ω . A person of mass M is standing on it. At one instant, the person jumps off the round, radially away from the centre of the round (as seen from the round). The speed of the round afterwards is

Moderate

A

2ω
B

ω
C

ω/2
D

0

Solution

L_i = (MR² + MR²)ω = 2MR²ω
L_f = MR² x ω + M x ω^'Rx R = 2MR²ω^'
Conserving angular momentum,
2MR²ω^' = 2MR²ω ⇒ ω^' = ω [Here tangential velocity ω^'R of the person produces angular momentum of the person]

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