Modulation

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Question

A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.

Moderate

Solution

$\begin{array}{l} Here, v_{m} = 10 k H z, A_{m} = 10 V \\ v_{c} = 1 M H z = 1000 k H z, A_{c} = 20 V \\ Modulation index, μ = \frac{A_{m}}{A_{c}} = \frac{10}{20} = 0.5 \\ The side bands are \\ U S B = v_{c} + v_{m} = 1000 + 10 = 1010 k H z \\ L S B = v_{c} - v_{m} = 1000 - 10 = 990 k H z \end{array}$

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Modulation

Remember concepts with our Masterclasses.

A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.

Here, vm=10kHz,Am=10Vvc=1 MHz=1000 kH z, Ac=20 VModulation index, μ=AmAc=1020=0.5 The side bands are USB=vc+vm=1000+10=1010 kHzLSB=vc−vm=1000−10=990 kHz

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