A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V . The modulation index and difference between the two side band frequencies are
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
0.25 ; 1×108Hz
b
4 ; 1×108Hz
c
0.25 ; 2×108Hz
d
4 ; 2×108Hz
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given : fm=100MHz=100×106Hz , fc = 300 GHz Am=100V, Ac=400V We know that, Range of frequency in case of Amplitude modulation is (fc−fm) to (fc+fm) . ∴ Band width=2fm = =2×100×106Hz = =2×108Hz and Modulation Index = AmAc = 100400 = 0.25
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V . The modulation index and difference between the two side band frequencies are