Q.
A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V . The modulation index and difference between the two side band frequencies are
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a
0.25 ; 1×108Hz
b
4 ; 1×108Hz
c
0.25 ; 2×108Hz
d
4 ; 2×108Hz
answer is C.
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Detailed Solution
Given : fm=100MHz=100×106Hz , fc = 300 GHz Am=100V, Ac=400V We know that, Range of frequency in case of Amplitude modulation is (fc−fm) to (fc+fm) . ∴ Band width=2fm = =2×100×106Hz = =2×108Hz and Modulation Index = AmAc = 100400 = 0.25
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