Questions
A metal baII of mass 2 kg moving with a velocity of 36 km/h has an head-on collision with a stationary ball of 3 kg. If after the collision, the two balls move together, the loss in K.E due to collision is
a
40 J
b
60 J
c
100 J
d
140 J
detailed solution
Correct option is B
Applying the law of conservation of momentum, we have2×10=(2+3)∨ (∵36km/h=10m/s) ∴ V=4m/s Loss of K.E. =12×2×(10)2−12×5×(4)2 = 60 JTalk to our academic expert!
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