A metal ball immersed in alcohol weights W1 at 0°C and W2 at 59°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that

The upthrust is given by  43πRt3ρtgHere   Rt3=R031+γmtand    ρt=ρ0/1+γatSo, the upthrust at t°C is given by          =43πR031+γmt×ρ0/1+γatg=43πR03ρ0g1+γmt/1+γatAs γm<γa, hence upthrust at t°C < upthrust at 0°C. So, the upthrust is decreased. Hence weight in liquid gets increased.