A metal ball immersed in alcohol weights $$W1$$ at $$0$$°C and $$W2$$ at $$59$$°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that

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Infinity Learn · Accepted Answer

The upthrust is given by  $$43$$$$π$$$$Rt3$$ρtgHere   $$Rt3=R031+$$γmtand    ρ$$t=$$ρ$$0/1+$$γatSo, the upthrust at t°C is given by          $$=43$$$$π$$$$R031+$$γmt×ρ$$0/1+$$γ$$atg=43$$$$π$$$$R03$$ρ$$0g1+$$γ$$mt/1+$$γatAs γm<γa, hence upthrust at t°C < upthrust at $$0$$°C. So, the upthrust is decreased. Hence weight in liquid gets increased.

	Column - I		Column - II
a	$γ_{g} < γ_{R}$	p	liquid level rises continuously from beginning
b	$γ_{g} = γ_{R}$	q	liquid level falls continuously from beginning
c	$γ_{g} > γ_{R}$	r	liquid level remains same
d	$γ_{g} = 0$	s	liquid level first falls and then rises

A metal ball immersed in alcohol weights W₁ at 0°C and W₂ at 59°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that

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A metal ball immersed in alcohol weights W1 at 0°C and W2 at 59°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that

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A metal ball immersed in alcohol weights W₁ at 0°C and W₂ at 59°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown that