A metal ball of mass 2 kg moving with a velocity of 36 km/h has an head on collision with a stationary ball of mass 3 kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is

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40 J

60 J

100 J

140 J

answer is B.

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Detailed Solution

v=36 km/h=10 m/s By law of conservation of momentum2×10=(2+3) V⇒V=4 m/sLoss in K.E. =12×2×(10)2−12×5×(4)2=60 J

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