First slide

Magnetic flux and induced emf

Question

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is $0 .2 \times 10^{- 4} T$ , then the e.m.f. developed between the two ends of the conductor is

Moderate

A

$5 mV$
B

$5 \times 10^{- 4} V$
C

$50 mV$
D

$50 μV$

Solution

$e = \frac{1}{2} {Bωr}^{2} = \frac{1}{2} \times 0 .2 \times 10^{- 4} \times 5 \times (1)^{2} = 50 μV$

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