Download the app

Questions  

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is  0.2×104T, then the e.m.f. developed between the two ends of the conductor is

a
5 mV
b
5×10−4V
c
50 mV
d
50 μV

detailed solution

Correct option is D

e=12Bωr2=12×0.2×10−4×5×(1)2=50μV

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The diagram shows a circuit having a coil of resistance R=2.5Ω and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.

At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.


phone icon
whats app icon