Questions
A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is then the e.m.f. developed between the two ends of the conductor is
detailed solution
Correct option is D
e=12Bωr2=12×0.2×10−4×5×(1)2=50 μVTalk to our academic expert!
Similar Questions
A uniform conducting rod of length l is rotating with uniform angular velocity about point P in uniform magnetic field B as shown. Calculate VP – VQ.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests