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A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is 0.2 × 104 T then the e.m.f. developed between the two ends of the conductor is

a
5 mV
b
5 × 10 V
c
50 mV
d
50 μV

detailed solution

Correct option is D

e=12Bωr2=12×0.2×10−4×5×(1)2=50 μV

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