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Q.

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is 0.2 × 10−4 T then the e.m.f. developed between the two ends of the conductor is

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a

5 mV

b

5 × 10 V

c

50 mV

d

50 μV

answer is D.

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Detailed Solution

e=12Bωr2=12×0.2×10−4×5×(1)2=50 μV
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