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Q.

A metal cube of side length 8.0 cm has its upper surface displaced with respect to the bottom by 0.10mm when tangential force of 4×104N  is applied at the top with bottom surface fixed. The rigidity modulus of the material of the cube is

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a

4×109Nm−2

b

5×109Nm−2

c

8×109Nm−2

d

108 Nm−2

answer is B.

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Detailed Solution

Rigidity modulus η=F/Atanθ tanθ=0.10×10−38×10−2=1800 η=4×104×8008×8×10−4=5×109N/m2
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