Questions

A metal meter scale gives correct measurement at  ${40}^{0}C$  it is generally used at a temperature of ${0}^{0}C$ . Find the correction to be made for every meter  $\left(\alpha ={10}^{-6}{/}^{0}C\right)$

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By Expert Faculty of Sri Chaitanya
a
4×10−5m
b
c
4×10−5mmust be deduted
d
none of the above
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detailed solution

Correct option is C

change in length is Δl=lαΔt  l is initial length of rod =1m;α is coefficient of linear expansion=10-6/C  0 Δt  is change in temperatue; decreased from 400C to 00C Δl=1×10−6×40 Δl=4×10−5mIf t2

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If a scale is made up of a material at temp ${t}_{1}^{0}C$  if temperature is changed to ${{t}_{2}}^{0}C$$\left({t}_{2}<{t}_{1}\right)$ then( coefficient of linear expansion is positive)

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