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A metal meter scale gives correct measurement at $40^{0} C$ it is generally used at a temperature of $0^{0} C$ . Find the correction to be made for every meter $(α = 10^{- 6} /^{0} C)$

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4×10−5m

4×10−5mto be added

4×10−5mmust be deduted

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detailed solution

Correct option is C

change in length is Δl=lαΔt l is initial length of rod =1m;α is coefficient of linear expansion=10-6/C 0 Δt is change in temperatue; decreased from 400C to 00C Δl=1×10−6×40 Δl=4×10−5mIf t2

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A metal meter scale gives correct measurement at 400C it is generally used at a temperature of 00C . Find the correction to be made for every meter α=10−6/0C

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A metal meter scale gives correct measurement at $40^{0} C$ it is generally used at a temperature of $0^{0} C$ . Find the correction to be made for every meter $(α = 10^{- 6} /^{0} C)$