First slide
Thermal expansion
Question

A metal meter scale gives correct measurement at  400C  it is generally used at a temperature of 00C . Find the correction to be made for every meter  α=106/0C

Moderate
Solution

change in length is Δl=lαΔt  l is initial length of rod =1m;α is coefficient of linear expansion=10-6/C  0 Δt  is change in temperatue; decreased from 400C to 00C Δl=1×106×40 Δl=4×105m

If t2<t1  so correction must be deducted.

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