Questions
A metal piece weighing 15 g is heated to and the immersed in a mixture of ice and water in thermal equilibrium. The volume of the mixture is found to be reduced by 0.15 with the temperature of the mixture remaining constant. Find the specific heat of the metal. Given specific gravity of ice = 0.92, specific gravity of water at = 1.0, latent heat of fusion of ice =
detailed solution
Correct option is A
mρice-mρH2O=0.15⇒m=0.15×0.920.08Hlost=Hgained⇒15×S×100=0.15×0.920.08×80 ⇒S=0.092 cal/g0CTalk to our academic expert!
Similar Questions
I. Speed of any point on rigid body executing rolling motion can be calculated by the expression
where r is the distance of point from instantaneous centre of rotation.
II. Rolling motion of rigid body can be considered as a pure rotation about instantaneous centre of rotation.
Which of the above statement{s} is/are correct?
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