Questions
A metal piece weighing 15 g is heated to and then immersed in a mixture of ice and water at the thermal equilibrium. The volume of the mixture is found to be reduced by 0.15 with the temperature of mixture remaining constant. Find the specific heat of the metal. Given specific gravity of ice = 0.92, specific gravity of water at
detailed solution
Correct option is A
mρice-mρH2o = 0.15m = 0.15×0.920.08∴ Hlost = Hgained ⇒ 15×S×100 = 0.15×0.920.08×80S = 0.092 cal/gm0CTalk to our academic expert!
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