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A metal rod has a length of 1m at $30^{\circ} C . α$ of metal is $2.5 \times 10^{- 5} /^{0} C$ . The temperature at which it will be shortened by 1mm is

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−300C

−20∘C

−100C

25∘C

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detailed solution

Correct option is C

2.5×10−5=−10−31×ΔtΔt=−40t2−t1=−40t2=−40+30=−10∘C

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A metal rod has a length of 1m at 30∘C.α of metal is 2.5×10−5/0C . The temperature at which it will be shortened by 1mm is

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A metal rod has a length of 1m at $30^{\circ} C . α$ of metal is $2.5 \times 10^{- 5} /^{0} C$ . The temperature at which it will be shortened by 1mm is