Q.

A metal rod has a length of 1m at 300C , 'α' of metal is 2.5×10−5/0C, the temperature at which it will be shortened by 1mm is

Moderate

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−300C

−400C

−100C

100C

answer is 3.

(Detailed Solution Below)

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Detailed Solution

coefficient of linear expansion of solid isα=ΔllΔthere Δl =-1mm=-10-3m=decrease in lengthl is initial length=1m; Δt is change in temperature;initial temperature = 300C; α=2.5x10-5/C 0 substitute given values in above equation2.5×10−5=−10−31×t2−30t2−30=−12.5×10−2=−1002.5t2−30=−40t2=−40+30=−100C=temperature at which rod will be shortened

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