A metal rod of resistance $$20$$ Ω is fixed along a diameter of a conducting ring of radius $$0.1$$ m and lies in an $$x-y$$ plane. There is a magnetic field B→$$=(50$$ $$T)k^$$. The ring rotates with an angular velocity ω$$=20$$ $$rad/s$$ about its axis. An external resistance of $$10$$ Ω is connected acrossthe centre of the ring and rim. The current through external resistance is

Question

A metal rod of resistance $$20$$ Ω is fixed along a diameter of a conducting ring of radius $$0.1$$ m and lies in an $$x-y$$ plane. There is a magnetic field B→$$=(50$$ $$T)k^$$. The ring rotates with an angular velocity ω$$=20$$ $$rad/s$$ about its axis. An external resistance of $$10$$ Ω is connected acrossthe centre of the ring and rim. The current through external resistance is

Infinity Learn · Accepted Answer

Potential difference between centre of the ring and the rim $$isV=12B$$ω$$R2=12(50)(2)(0.1)2=5VNow$$ the circuit can be drawn as follows:$$i=510+5=13A$$

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