First slide
Motional EMF
Question

A metal rod of resistance 20 Ω is fixed along a diameter of a conducting ring of radius 0.1 m and lies in an x-y plane. There is a magnetic field B=(50 T)k^. The ring rotates with an angular velocity ω=20 rad/s about its axis. An external resistance of 10 Ω is connected across
the centre of the ring and rim. The current through external resistance is

Difficult
Solution

Potential difference between centre of the ring and the rim is

V=12BωR2

=12(50)(2)(0.1)2=5V

Now the circuit can be drawn as follows:

i=510+5=13A

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