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A metal rod of resistance 20 Ω is fixed along a diameter of a conducting ring of radius 0.1m and lies on x-y plane. There is a magnetic field B=(50T)k^. The ring rotates with an angular velocity ω = 20 rad/sec about its axis. An external resistance of 10Ω is connected across the center of the ring and rim. The current through external resistance is

a
14
b
12
c
13
d
Zero

detailed solution

Correct option is C

ε=Bωr22=5 Volt. Now current I=εR1+R2=13A

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A uniform conducting rod of length l is rotating with uniform angular velocity ω about point P in uniform magnetic field B as shown. Calculate VP – VQ.


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