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Q.

A metal rod is subjected to tensile force and longitudinal strain produced in the rod is 0.02. If Poisson’s ratio of the metal is 0.3, the change produced in its volume is

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a

0.3%

b

0.8%

c

0.6%

d

0.9%

answer is B.

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Detailed Solution

V=πr2l∴    ΔVV=2Δrr+ΔllBut Δrr=−σ ×  Δll∴   ΔV×100V=1−2σ  ×  Δll× 100%                   =1−2 × 0.3  ×  0.02  ×  100%=0.8%
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