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A metal rod of Young's modulus $2.5 \times 10^{10} N m^{- 2}$ undergoes an elastic strain of 0.01% the energy per unit volume stored in the rod in $joule / m^{3}$ is

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detailed solution

Correct option is C

ΔEV=12Y.(strain)2 =12×2.5×1010×0.011002=12×2.5×1010×10−8=1.25×102=125

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A metal rod of Young's modulus 2.5×1010Nm−2 undergoes an elastic strain of 0.01% the energy per unit volume stored in the rod in joule/m3 is

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A metal rod of Young's modulus $2.5 \times 10^{10} N m^{- 2}$ undergoes an elastic strain of 0.01% the energy per unit volume stored in the rod in $joule / m^{3}$ is