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A metal sphere weighing 50 grms in air is suspended by a thread in an oil of specific gravity 0.4. If the tension in the thread is 40 grm wt. The specific gravity of the metal sphere is

a
2
b
0.8
c
4
d
8

detailed solution

Correct option is A

T=w(1−dℓdb)⇒T=w(1−dLdwdbdw)                 T=50(1−R.D1R.D2)                 40=50(1−0.4R.D2)                 45=1−0.4R.D2⇒0.4R.D2=1−45=15                 R.D2=0.4×51=2 Relative density of body is = 2

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